Consider this system of equations: 2x + 1/4 y= 3 (equation A) 2/3 x - y = 6 (equation B)The expressions that give the value of y are ___ and ___ .The solution for the given system is ___.
Accepted Solution
A:
we have that 2x + 1/4 y= 3 (equation A) 2/3 x - y = 6 (equation B)
Part a) The expressions that give the value of y are equation A 2x + 1/4 y= 3-----> (1/4)y=3-2x------> y=4*(3-2x)----> y=12-8x
equation B 2/3 x - y = 6------> y=(2/3)x-6
the answer Part a) is The expressions that give the value of y are y=12-8x-------> equation A y=(2/3)x-6-----> equation B
Part b) The solution for the given system y=12-8x y=(2/3)x-6